RAJASTHAN ­ PET Rajasthan PET Solved Paper-2009

  • question_answer
    The distance of the point P (1,2,3) from the line which passes through the point A (4,2,2) and parallel to the vector\[2\hat{i}+3\hat{j}+6\hat{k},\]is

    A)  \[\sqrt{10}\]     

    B)  \[\sqrt{7}\]

    C)  \[\sqrt{5}\]               

    D)  \[1\]

    Correct Answer: A

    Solution :

     The equation of line which passes through the point A (4,2,2) and parallel to the vector \[2\hat{i}+3\hat{j}+6\hat{k}\]is \[\frac{x-4}{2}=\frac{y-2}{3}=\frac{z-2}{6}\] Distance of point P from the line \[=\sqrt{\Sigma {{({{x}_{1}}-{{x}_{2}})}^{2}}-{{(\Sigma l({{x}_{1}}-{{x}_{2}}))}^{2}}}\] \[=\sqrt{\begin{align}   & {{(1-4)}^{2}}+{{(2-2)}^{2}}+{{(3-2)}^{2}}-\{2(1-4) \\  & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+3(2-2)+6(3-2){{\}}^{2}} \\ \end{align}}\] \[=\sqrt{9+0+1-{{(-6+0+6)}^{2}}}=\sqrt{10}\]


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