RAJASTHAN ­ PET Rajasthan PET Solved Paper-2009

  • question_answer
    A simple wave motion represents by\[y=5(\sin 4\pi t+\sqrt{3}\cos 4\pi t)\]. Its amplitude is

    A)  5                   

    B)  5\[\sqrt{3}\]

    C)  \[10\sqrt{3}\]               

    D)  10

    Correct Answer: A

    Solution :

     \[y=5(\sin 4\pi t+\sqrt{3}\cos 4\pi t)\] \[y=5(\sin 4\pi t+5\sqrt{3}\cos 4\pi t)\] \[A=\sqrt{A_{1}^{2}+A_{2}^{2}}\] \[A=\sqrt{{{(5)}^{2}}+{{(5\sqrt{3})}^{2}}}\] \[=\sqrt{25+75}=\sqrt{100}=10\]


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