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  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2009

  • question_answer
    One end of string of length\[l\]is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v, the net force on the particle (directed towards the centre) is

    A)  zero              

    B)  \[T-\frac{m{{v}^{2}}}{I}\]

    C)  \[T\]              

    D)  \[T+\frac{m{{v}^{2}}}{I}\]

    Correct Answer: D

    Solution :

     When particle moves in a circle, then the resultant force must act towards the centre and its magnitude F must satisfy \[F=\frac{m{{v}^{2}}}{I}\] This resultant force is directed towards the centre it is called centripetal force.This force originates from the tension T Hence,      \[F=\frac{m{{v}^{2}}}{I}=T\]


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