RAJASTHAN ­ PET Rajasthan PET Solved Paper-2009

  • question_answer
    The half-life period of a radioactive substance is 3 days. Three fourth of substance decays in

    A)  3 days            

    B)  6 days

    C)  9 days            

    D)  12 days

    Correct Answer: B

    Solution :

     \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] Remaining part, \[={{N}_{0}}-\frac{3}{4}{{N}_{0}}\]  \[=\frac{1}{4}{{N}_{0}}\] \[\frac{{{N}_{0}}}{4}={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] \[{{\left( \frac{1}{2} \right)}^{2}}={{\left( \frac{1}{2} \right)}^{n}}\] \[n=2\] Time = Half year\[\times \]Number of half year \[=3\times 2=6\]days


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