RAJASTHAN ­ PET Rajasthan PET Solved Paper-2009

  • question_answer
    The frequency and velocity of sound wave are 600 Hz and 360 m/s respectively. Phase difference between two particles of medium are\[60{}^\circ ,\]the minimum distance between these two particles will be

    A)  10 cm           

    B)  15 cm

    C)  20 cm           

    D)  50 cm

    Correct Answer: B

    Solution :

     Velocity of wave v)= 360 m/s Frequency, \[n=600\text{ }Hz\] Phase difference, \[\phi =60{}^\circ \] If the minimum distance between two points is\[\Delta x\]then \[\Delta x=\frac{\lambda }{2\pi }\times \Delta \phi \] Or \[\Delta x=\frac{V}{2\pi n}\times \Delta \phi \] Or \[\Delta x=\frac{360}{2\pi \times 600}\times 60\] \[\Delta x=\frac{360}{2\pi \times 600}\times \frac{\pi }{3}\] \[\Delta x=\frac{1}{10}m\] \[\Delta x=10\,m\]


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