A) \[(AB)'=B'A'\]
B) \[{{(AB)}^{\theta }}={{B}^{\theta }}{{A}^{\theta }}\]
C) \[\overline{AB}=\overline{B}\,\,\overline{A}\]
D) \[{{(AB)}^{-1}}={{B}^{-1}}{{A}^{-1}}\]
Correct Answer: C
Solution :
Option [c] is correct, \[\because \] \[\overline{AB}=\overline{A}\,\overline{B}\]
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