A) \[\frac{{{x}^{2}}-{{y}^{2}}}{a-b}=\frac{2xy}{h}\]
B) \[\frac{{{x}^{2}}+{{y}^{2}}}{a+b}=\frac{xy}{2h}\]
C) \[\frac{{{x}^{2}}-{{y}^{2}}}{a-b}=\frac{xy}{h}\]
D) None of these
Correct Answer: A
Solution :
Given, equation of pair of lines is \[a{{x}^{2}}+hxy+b{{y}^{2}}=0\] \[\therefore \]Equation of angle bisector is \[\frac{{{x}^{2}}-{{y}^{2}}}{a-b}=\frac{xy}{h/2},=\frac{2xy}{h}\]
You need to login to perform this action.
You will be redirected in
3 sec
