A) 1
B) \[-1\]
C) 2
D) \[-i\]
Correct Answer: B
Solution :
Given, \[x=\frac{\sqrt{3}+i}{2}\] \[\Rightarrow \] \[x=-{{\omega }^{2}}\] \[\left( \because {{\omega }^{2}}=\frac{-i-\sqrt{3}}{2} \right)\] \[\Rightarrow \] \[{{x}^{3}}={{(-1)}^{3}}{{({{\omega }^{2}})}^{3}}\] \[\Rightarrow \] \[{{x}^{3}}=-1\]
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