A) \[s{{p}^{3}}\]to\[s{{p}^{2}}\]
B) \[sp\]to \[s{{p}^{2}}\]
C) \[s{{p}^{2}}\]to\[sp\]
D) \[sp\]to\[s{{p}^{3}}\]
Correct Answer: C
Solution :
\[\underset{s{{p}^{2}}}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-N{{H}_{2}}}}\,\xrightarrow[{}]{{{P}_{2}}{{O}_{5}}}\underset{sp}{\mathop{C{{H}_{3}}-C\equiv N}}\,+{{H}_{2}}O\] In the above dehydration reaction the hybridised state of carbon is changing from \[s{{p}^{2}}\]tosp.
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