A) \[2SO_{4}^{2-}\xrightarrow[{}]{{}}{{S}_{2}}O_{3}^{2-}+2\frac{1}{2}{{O}_{2}}+2{{e}^{-}}\]
B) \[C{{u}^{2+}}+2{{e}^{-}}\xrightarrow[{}]{{}}Cu\]
C) \[2{{H}_{2}}O\xrightarrow[{}]{{}}{{O}_{2}}+4{{H}^{+}}+4{{e}^{-}}\]
D) \[2{{H}^{+}}+2{{e}^{-}}\xrightarrow[{}]{{}}{{H}_{2}}\]
Correct Answer: C
Solution :
Electrolysis of aqueous\[CuS{{O}_{4}}\]solution by unreactive Pt electrodes is as \[C{{u}^{2+}}+2{{e}^{-}}\xrightarrow[{}]{{}}Cu;\] at cathode \[2{{H}_{2}}O\xrightarrow[{}]{{}}{{O}_{2}}+4{{H}^{+}}+4{{e}^{-}};\] at anode The\[SO_{4}^{2-}\]does not oxidises in this process because the standard reduction potential of \[{{S}_{2}}O_{8}^{2-}/SO_{4}^{2-}\]pair is more than the water.
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