A) \[9\times {{0}^{5}}\]
B) \[5\times {{10}^{9}}\]
C) \[2.25\times {{10}^{11}}\]
D) \[3\times {{10}^{19}}\]
Correct Answer: B
Solution :
\[{{n}_{e}}{{n}_{h}}={{({{n}_{i}})}^{2}}\] \[{{n}_{e}}\times 4.5\times {{10}^{22}}={{(1.5\times {{10}^{16}})}^{2}}\] \[{{n}_{e}}=\frac{2.25\times {{10}^{32}}}{4.5\times {{10}^{22}}}\] \[{{n}_{e}}=5\times {{10}^{9}}\]
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