A) \[W{{m}^{-1}}{{K}^{-1}}\]
B) \[J{{K}^{-1}}\]
C) \[WmK\]
D) \[JK\]
Correct Answer: A
Solution :
Thermal conductivity \[=\frac{\Delta Q}{tA\Delta \theta }=\frac{Jm}{{{m}^{2}}sK}=W/m-K\]
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