RAJASTHAN ­ PET Rajasthan PET Solved Paper-2008

  • question_answer
    A rod AB is 1 m long. The temperature of its one end A is maintained at \[100{}^\circ C\] and other end B at WC. the temperature at a distance of 60 cm from point B is

    A)  \[64{}^\circ C\]             

    B)  \[36{}^\circ C\]

    C)  \[46{}^\circ C\]            

    D)  \[72{}^\circ C\]

    Correct Answer: A

    Solution :

     Let the temperature at distance 60 cm from point B is \[\theta \] where K = coefficient of thermal conductivity A = area of rod \[\frac{KA(100-\theta )}{40}=\frac{KA(\theta -10)}{60}\] Or \[\frac{100-\theta }{2}=\frac{\theta -10}{3}\] or        \[300-3\theta =26-20\] or             \[5\theta =320\] or              \[\theta =64{}^\circ C\]


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