A) 68
B) 48
C) 12
D) 8
Correct Answer: A
Solution :
According to Graham's law of diffusion \[\frac{{{r}_{1}}}{{{r}_{2}}}=\sqrt{\frac{{{M}_{2}}}{{{M}_{1}}}}\] \[{{r}_{X}}=\frac{{{r}_{N{{H}_{3}}}}}{2}\] \[{{M}_{N{{H}_{3}}}}=17\] \[{{M}_{X}}=?\] \[\frac{{{r}_{N{{H}_{3}}}}}{{{r}_{X}}}=\sqrt{\frac{{{M}_{X}}}{{{M}_{N{{H}_{3}}}}}}\] \[2=\sqrt{\frac{{{M}_{X}}}{17}}\]
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