A) \[60{}^\circ \]
B) \[30{}^\circ \]
C) \[45{}^\circ \]
D) \[90{}^\circ \]
Correct Answer: A
Solution :
Magnetic dip or magnetic inclination is given by \[\tan \delta =\frac{{{B}_{V}}}{{{B}_{H}}}\] Given \[{{B}_{H}}=\frac{1}{\sqrt{2}}{{B}_{V}}\] \[\frac{{{B}_{V}}}{{{B}_{H}}}=\sqrt{3}\] From Eqs. (i) and (ii), we get \[\tan \delta =\sqrt{3}\] \[\delta =60{}^\circ \]
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