A) \[-1\]
B) 0
C) 1
D) None of these
Correct Answer: B
Solution :
Given, \[f(x)=\frac{\sin x}{x}\] \[\therefore \] \[\underset{x\to \infty }{\mathop{\lim }}\,\frac{\sin x}{x}=\underset{x\to \infty }{\mathop{\lim }}\,\frac{1}{x}.\underset{x\to \infty }{\mathop{\lim }}\,\sin x\] \[=0\times \] finite value \[=0\]
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