A) \[1.57\times {{10}^{-10}}\]
B) \[1\times {{10}^{-10}}\]
C) \[3.24\times {{10}^{-6}}\]
D) \[1\times {{10}^{-6}}\]
Correct Answer: A
Solution :
Solubility of\[AgCl=1.8\times {{10}^{-3}}g/L\] \[=\frac{1.8\times {{10}^{-3}}}{143.5}mol/L\] \[=1.25\times {{10}^{-5}}mol/L\] Solubility product of \[AgCl={{(solubility)}^{2}}\] \[={{(1.25\times {{10}^{-5}})}^{2}}\] \[=1.57\times {{10}^{-10}}\]
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