A) 6 and +3
B) 3 and zero
C) 4 and+2
D) 3 and +3
Correct Answer: A
Solution :
In\[{{K}_{3}}Cr{{({{C}_{2}}{{O}_{4}})}_{3}},\]chromium (Or) is attached by three divalent oxalate ligand hence the coordination number of Cr is 6. Let the oxidation^siate of Cr is\[x\]in \[{{K}_{3}}Cr{{({{C}_{2}}{{O}_{4}})}_{3}}\] \[+3+x+3(-2)=0\] \[3+x-6=0\] \[x-3=0\] \[x=+3\]
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