A) 3, 3-dimethyl-l-butene
B) 2, 3-dimethyl-2-butene
C) 2, 3-dimethyl-l-butene
D) cis and trans isomers of product [b].
Correct Answer: B
Solution :
On the dehydration of alcohol, a more stable alkene is formed as major product. According to Saytzeffs rule a more substituted alkene is more stable. \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}\xrightarrow[\Delta ]{Conc.{{H}_{2}}S{{O}_{4}}}\] \[\underset{2,3-dimethyl2-butene}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,=\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}}}\,\]
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