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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2006

  • question_answer
    The binding energies per nucleon for a deuteron and an \[\alpha \]-particle are\[{{x}_{1}}\]and\[{{x}_{2}}\]respectively. What will be the energy Q released in the reaction? \[_{1}{{H}^{2}}{{+}_{1}}{{H}^{2}}{{\xrightarrow[{}]{{}}}_{2}}H{{e}^{4}}+Q\]

    A)  \[4({{x}_{1}}+{{x}_{2}})\]       

    B)  \[({{x}_{1}}{{x}_{2}})\]

    C)  \[({{x}_{1}}+{{x}_{2}})\]         

    D)  \[4({{x}_{2}}{{x}_{1}})\]

    Correct Answer: D

    Solution :

     \[\underset{2{{x}_{1}}}{\mathop{_{1}{{H}^{2}}}}\,+\underset{2{{x}_{1}}}{\mathop{_{1}{{H}^{2}}}}\,\xrightarrow[{}]{{}}\underset{4{{x}_{2}}}{\mathop{_{2}H{{e}^{4}}}}\,+Q\] \[\therefore \] \[Q=4{{x}_{2}}-2{{x}_{1}}-2{{x}_{1}}\] \[=4({{x}_{2}}-{{x}_{1}})\]


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