RAJASTHAN ­ PET Rajasthan PET Solved Paper-2005

  • question_answer
    The equation of the tangent of the hyperbola \[2{{x}^{2}}-3{{y}^{2}}=6\]which is parallel to the line \[y=3x+4,\]is

    A)  \[y=3x-5\]

    B)  \[y=3x+5\]

    C) \[y=3x+5\]and\[y=3x-5\]

    D)  None of the above

    Correct Answer: C

    Solution :

     Given, hyperbola is\[2{{x}^{2}}-3{{y}^{2}}=6\] \[\Rightarrow \] \[\frac{{{x}^{2}}}{3}-\frac{{{y}^{2}}}{2}=1\] \[\therefore \] \[{{a}^{2}}=3,{{b}^{2}}=2\] and       \[y=3x+4\] \[\therefore \] \[m=3\] \[\therefore \]Equation of tangent is \[y=mx\pm \sqrt{({{a}^{2}}{{m}^{2}}-{{b}^{2}})}\] \[\Rightarrow \] \[y=3x\pm \sqrt{3.{{(3)}^{2}}-2}\] \[\Rightarrow \] \[y=3x\pm \sqrt{27-2}\] \[\therefore \] \[y=3x\pm 5\]


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