question_answer

\[SnC{{l}_{4}}+2FeC{{l}_{2}}\xrightarrow[{}]{{}}SnC{{l}_{2}}+2FeC{{l}_{3}}\] In this reaction, oxidising agent and reducing agent are respectively

A)  \[SnC{{l}_{2}}\]and \[FeC{{l}_{3}}\]  

B)  \[FeC{{l}_{3}}\]and\[SnC{{l}_{4}}\]

C)  \[FeC{{l}_{2}}\] and \[SnC{{l}_{4}}\]

D)  \[SnC{{l}_{4}}\]and \[FeC{{l}_{3}}\]

Correct Answer: D

Solution :

  Hence,\[SnC{{l}_{4}}\]is oxidising agent while\[FeC{{l}_{2}}\]is reducing agent.