A) \[NaOH\]
B) \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\]
C) \[{{H}_{2}}{{O}_{2}}\]
D) \[{{H}_{2}}S{{O}_{4}}\]
Correct Answer: C
Solution :
\[{{H}_{2}}{{O}_{2}}\]shows the both oxidant and reductant behaviour. \[{{H}_{2}}{{O}_{2}}\xrightarrow[{}]{{}}{{H}_{2}}O+[O]\] (oxidant) \[{{H}_{2}}{{O}_{2}}\xrightarrow[{}]{{}}{{O}_{2}}+2{{H}^{+}}\] (reductant)
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