A) \[{{\mu }_{0}}\,\times \,{{10}^{-19}}\,T\]
B) \[1.6\,\times {{\mu }_{0}}\,\times \,{{10}^{-19}}\,T\]
C) \[3{{\mu }_{0}}\,\times \,{{10}^{-19}}\,T\]
D) \[2{{\mu }_{0}}\,\times \,{{10}^{-19}}\,T\]
Correct Answer: A
Solution :
The magnetic field at centre \[B=\frac{{{\mu }_{0}}I}{2r}=\frac{{{\mu }_{0}}(q-t)}{2r}\] \[=\frac{{{\mu }_{0}}\times 2\times 1.6\times {{10}^{-19}}}{2\times 0.8\times 2}\] \[B={{\mu }_{0}}\times {{10}^{-19}}T\]
You need to login to perform this action.
You will be redirected in
3 sec
