RAJASTHAN ­ PET Rajasthan PET Solved Paper-2005

  • question_answer
    An iron nail of 200 g is fitted in a wood piece with a speed of 50 m/s by a hammer of 1 kg. If specific heat of iron is\[0.105\text{ }cal/g{}^\circ C\]and half of the total energy given to nail is transfered in heat, then what will be the rise in temperature of nail?                                    

    A)  \[1.42{}^\circ C\]            

    B)  \[9.2{}^\circ C\]            

    C)  \[10.5{}^\circ C\]            

    D)  \[12.1{}^\circ C\]           

    Correct Answer: A

    Solution :

     According to question \[\frac{1}{2}\left( \frac{1}{2}m{{v}^{2}} \right)=ms\,\Delta \theta \] \[\therefore \] \[\Delta \theta =\frac{{{v}^{2}}}{4s}\] \[=\frac{50\times 50}{4\times 0.105\times 4.18\times {{10}^{3}}}\] \[=1.42{}^\circ C\]


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