A) \[1.42{}^\circ C\]
B) \[9.2{}^\circ C\]
C) \[10.5{}^\circ C\]
D) \[12.1{}^\circ C\]
Correct Answer: A
Solution :
According to question \[\frac{1}{2}\left( \frac{1}{2}m{{v}^{2}} \right)=ms\,\Delta \theta \] \[\therefore \] \[\Delta \theta =\frac{{{v}^{2}}}{4s}\] \[=\frac{50\times 50}{4\times 0.105\times 4.18\times {{10}^{3}}}\] \[=1.42{}^\circ C\]You need to login to perform this action.
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