RAJASTHAN ­ PET Rajasthan PET Solved Paper-2005

  • question_answer
    The relation between relative change of volume \[\left( \frac{\Delta V}{V} \right)\] and relative change of pressure \[\left( \frac{\Delta p}{p} \right)\]  in adiabatic process is

    A)  \[\frac{1}{\gamma }\left( \frac{\Delta V}{V} \right)\]

    B)  \[\frac{1}{{{\gamma }^{2}}}\left( \frac{\Delta V}{V} \right)\]

    C)  \[-\gamma \left( \frac{\Delta V}{V} \right)\]

    D)  \[\gamma \left( \frac{\Delta V}{V} \right)\]

    Correct Answer: C

    Solution :

     For an adiabatic process\[P{{V}^{\gamma }}=\]constant. Differentiating both the sides \[dp{{V}^{\gamma }}+p\gamma {{V}^{\gamma -1}}dV=0\] \[\gamma p=\frac{dp}{-dV/V}\] \[\Rightarrow \] \[\frac{dp}{p}=\gamma \frac{dV}{V}\]


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