RAJASTHAN ­ PET Rajasthan PET Solved Paper-2005

  • question_answer
    A second pendulum is taken in a satellite moving at a height of 2R from the earth's surface. At that position the time period (in second) of pendulum will be

    A)  0                 

    B)  2

    C)  4                 

    D) \[\infty \]

    Correct Answer: D

    Solution :

     Acceleration due to gravity in satellite\[(g)=0\] Time period \[(T)=2\pi \sqrt{\frac{l}{g}}=\infty \]


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