A) \[\frac{7}{36}\]
B) \[\frac{1}{36}\]
C) \[\frac{1}{6}\]
D) None of these
Correct Answer: C
Solution :
Number of ways of getting the sum seven {(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)} \[\therefore \]Required probability \[=\frac{6}{36}=\frac{1}{6}\]
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