A) \[\frac{1}{x\sqrt{{{x}^{2}}+1}}\]
B) \[\frac{1}{\sqrt{{{x}^{2}}-1}}\]
C) \[\frac{1}{x\sqrt{1-{{x}^{2}}}}\]
D) \[\frac{1}{x\sqrt{{{x}^{2}}-1}}\]
Correct Answer: D
Solution :
\[y={{\sec }^{-1}}x\] On differentiating w.r.t.\[x,\]we get \[\frac{dy}{dx}=\frac{1}{x\sqrt{{{x}^{2}}-1}}\]
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