RAJASTHAN ­ PET Rajasthan PET Solved Paper-2004

  • question_answer
    The solubility product of two sparingly soluble electrolyte AX and BX are\[1\times {{10}^{-8}}\]and\[1\times {{10}^{-10}}\] respectively. Which of the following statement is correct?

    A)  Solubility of AX is 100 times more than BX.

    B)  Solubility of BX is 100 times more than AX.

    C)  Solubility of AX is 10 times more than BX.

    D)  Comparison of solubility cannot done from these data

    Correct Answer: C

    Solution :

     Relationship between solubility and solubility product of AX and BX salt is \[{{K}_{sp}}={{S}^{2}}\] Solubility of\[AX(S)=\sqrt{1\times {{10}^{-8}}}\] \[={{10}^{-4}}mol/L\] Solubility of \[BX(S)=\sqrt{1\times {{10}^{-10}}}={{10}^{-5}}mol/L\] Hence, the solubility of AX is 10 times more than BX.


You need to login to perform this action.
You will be redirected in 3 sec spinner