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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2004

  • question_answer
    The degree of dissociation of a weak carbonic acid of 0.1 M solution is 10%. The value of dissociation constant of this acid will

    A)  \[{{10}^{-5}}\]             

    B)  \[{{10}^{-4}}\]

    C)  \[{{10}^{-3}}\]             

    D)  \[{{10}^{-2}}\]

    Correct Answer: C

    Solution :

     Degree of dissociation \[(\alpha )=10%=\frac{10}{100}=0.1\] C (concentration)\[=0.1\text{ }M\] \[{{K}_{a}}={{\alpha }^{2}}C\] \[={{(0.1)}^{2}}\times 0.1\] \[={{10}^{-3}}\]


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