A) a primary alkyl halide
B) a gem dihalide
C) a primary or secondary alkyl halide
D) a secondary or tertiary alkyl halide
Correct Answer: C
Solution :
Primary or secondary alkyl halide is obtained by the reaction of hydrogen halide with unsymmetrical alkene. Example? \[C{{H}_{3}}-CH=C{{H}_{2}}+HBr\xrightarrow[{}]{{}}\underset{secondary\text{ }alkyl\text{ }halide}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}}}\,\] \[C{{H}_{3}}-CH=C{{H}_{2}}+HBr\xrightarrow[{}]{Peroxide}\] \[\underset{primary\text{ }alkyl\text{ }halide}{\mathop{C{{H}_{3}}C{{H}_{2}}-C{{H}_{2}}Br}}\,\]
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