A) \[C{{l}_{2}}O\]
B) \[O{{F}_{2}}\]
C) \[{{H}_{2}}O\]
D) \[S{{O}_{2}}\]
Correct Answer: D
Solution :
\[s{{p}^{3}}\]hybridization presents in\[C{{l}_{2}}O,O{{F}_{2}},{{H}_{2}}O\] etc. Molecules while\[s{{p}^{2}}\]hybridization presents in\[S{{O}_{2}}\]molecule.
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