A) 800 V, 2A
B) 300 V, 2A
C) 220V, 2.2 A
D) 100V, 2A
Correct Answer: C
Solution :
Here \[{{V}_{L}}={{V}_{C}}\] \[V=\sqrt{V_{R}^{2}+{{({{V}_{L}}-{{V}_{C}})}^{2}}}={{V}_{R}}=220\,V\] \[I=\frac{220}{100}=2.2A\]
You need to login to perform this action.
You will be redirected in
3 sec
