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  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2004

  • question_answer
    The velocity of sound in air is 333 m/s and the fundamental frequency of open pipe is 333 Hz. The length of pipe to produced second overtones will be

    A)  0.5 m              

    B)  1.0 m

    C)  1.5 m              

    D)  2 m

    Correct Answer: A

    Solution :

     The frequency of fundamental mode\[{{n}_{1}}=\frac{V}{2l}=333Hz\] The frequency of third harmonic (second overtone) \[=3\times 333\] \[\frac{3v}{2l'}=3\times 333\] \[l'=\frac{1}{2}=0.5m\]


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