RAJASTHAN ­ PET Rajasthan PET Solved Paper-2004

  • question_answer
    In the Young's double slit experiment, intensities of black and bright fringes are 1 and 4 respectively, the ratio of amplitudes of sources will be

    A)  1 : 1                

    B)  1 : 2

    C)  3 : 1                

    D)  1 : 4

    Correct Answer: B

    Solution :

     \[E=k{{a}^{2}}\Rightarrow E\propto {{a}^{2}}\] Or \[\frac{a_{1}^{2}}{a_{2}^{2}}=\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{1}{4}\] Or \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{1}{2}\]


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