2. Solved Papers
  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2003

  • question_answer
    If\[y=f(x)=\frac{ax+b}{cx-a},\]then\[x\]is equal to

    A)  \[\frac{1}{f(x)}\]

    B)  \[\frac{1}{f(y)}\]

    C)  \[yf(x)\]

    D)  \[f(y)\]

    Correct Answer: D

    Solution :

     \[\because \]\[y=f(x)=\frac{ax+b}{cx-a}\] \[\Rightarrow \] \[y(cx-a)=ax+b\] \[\Rightarrow \] \[(yc-a)x=b+ay\] \[\Rightarrow \] \[x=\frac{ay+b}{cy-a}=f(y)\]


You need to login to perform this action.
You will be redirected in 3 sec spinner