A) \[cos{{h}^{2}}x+sin{{h}^{2}}x=1\]
B) \[cos{{h}^{2}}x-sin{{h}^{2}}x=cos{{h}^{2}}x\]
C) \[1+tan{{h}^{2}}x=sec{{h}^{2}}x\]
D) \[cos{{h}^{2}}x-sin{{h}^{2}}x=1\]
Correct Answer: D
Solution :
\[cos{{h}^{2}}x-sin{{h}^{2}}x=1\]
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