A) \[\frac{4}{13}\]
B) \[\frac{17}{52}\]
C) \[\frac{1}{52}\]
D) \[\frac{1}{13}\]
Correct Answer: A
Solution :
Number of ways to draw a card from the pack of cards\[{{=}^{52}}{{C}_{1}}\] The probability that the card is diamond\[{{P}_{1}}=\frac{13}{52}\] The probability that the card is ace, \[{{P}_{2}}=\frac{4}{52}\] The probability that the card is diamond and ace \[{{P}_{3}}=\frac{1}{52}\] Hence, the probability that the card is diamond or ace is \[P={{P}_{1}}+{{P}_{2}}-{{P}_{3}}\] \[=\frac{13}{52}+\frac{5}{52}-\frac{1}{52}=\frac{16}{52}=\frac{4}{13}\]
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