A) \[\frac{5}{36}\]
B) \[\frac{1}{12}\]
C) \[\frac{1}{6}\]
D) None of these
Correct Answer: C
Solution :
Total number of ways in which sum of two dice is seven {(1,6), (2,5), (3, 4), (4.3), (5,2), (6,1)} \[\therefore \]Required probability\[=\frac{6}{36}=\frac{1}{6}\]
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