A) \[C{{H}_{2}}=C{{H}_{2}}\]
B) \[CH\equiv CH\]
C) \[C{{H}_{3}}-CH=CH-C{{H}_{3}}\]
D) \[C{{H}_{3}}C{{H}_{2}}-CH=C{{H}_{2}}\]
Correct Answer: A
Solution :
\[\underset{\begin{smallmatrix} ethylidene \\ chloride \end{smallmatrix}}{\mathop{\underset{C{{H}_{2}}Cl}{\overset{C{{H}_{2}}Cl}{\mathop{|}}}\,}}\,+\underset{\begin{smallmatrix} zinc \\ dust \end{smallmatrix}}{\mathop{Zn}}\,\xrightarrow[{}]{{}}\underset{ethene}{\mathop{\underset{C{{H}_{2}}}{\overset{C{{H}_{2}}}{\mathop{||}}}\,}}\,+ZnB{{r}_{2}}\]
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