A) n-hexane
B) n-hexene
C) \[C{{H}_{3}}-CH=C{{H}_{2}}\]
D) \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,=C{{H}_{3}}\]
Correct Answer: D
Solution :
\[\underset{2\text{ }-chloro\text{ }propane}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}}}\,+Na+C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}\] \[\xrightarrow[{}]{dry\,ether}\underset{2,3-dimethyl\text{ }butane}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}}}\,+2NaCl\]
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