A) \[{{v}^{2}}_{1}-v\frac{2}{2}=\frac{2h}{m}({{f}_{1}}-{{f}_{2}})\]
B) \[{{v}_{1}}+{{v}_{2}}={{\left[ \frac{2h}{m}({{f}_{1}}+{{f}_{2}}) \right]}^{2}}\]
C) \[{{v}^{2}}_{1}+{{v}^{2}}_{2}=\frac{2h}{m}({{f}_{1}}+{{f}_{2}})\]
D) \[{{v}_{1}}-{{v}_{2}}={{\left[ \frac{2h}{m}({{f}_{1}}-{{f}_{2}} \right]}^{1/2}}\]
Correct Answer: A
Solution :
\[hf=h{{f}_{0}}+\frac{1}{2}m{{v}^{2}}\] \[v_{1}^{2}=\frac{2h{{f}_{1}}}{m}-\frac{2h{{f}_{0}}}{m}\] \[v_{2}^{2}=\frac{2h{{f}_{2}}}{m}-\frac{2h{{f}_{0}}}{m}\] \[v_{1}^{2}-v_{2}^{2}=\frac{2h}{m}({{f}_{1}}-{{f}_{2}})\]
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