RAJASTHAN ­ PET Rajasthan PET Solved Paper-2003

  • question_answer
    Two positive point charges 12\[\mu \]C are 8\[\mu \]C are placed at a distance work done to bring closer 4 cm will be

    A)  5.8 J             

    B)  5.8 eV         

    C)  13 J             

    D)  13 eV            

    Correct Answer: C

    Solution :

     \[W={{U}_{f}}-{{U}_{i}}\] \[=9\times {{10}^{9}}\times {{q}_{1}}{{q}_{2}}\left[ \frac{1}{{{r}_{1}}}-\frac{1}{{{r}_{2}}} \right]\] \[=9\times {{10}^{9}}\times 12\times {{10}^{6}}\times 8\times {{10}^{-6}}\]                    \[\left[ \frac{1}{4\times {{10}^{-2}}}-\frac{1}{10\times {{10}^{-2}}} \right]\] \[=12.96J\] \[W=13J\]


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