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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2003

  • question_answer
    There is an electric field E in\[x-\]direction. If the work done on moving a charge 0.2 C through a distance of 2 m along a line making an angle \[60{}^\circ \] with the\[x-\]axis is 4.0, what is the value of E?

    A)  \[\sqrt{3}\]N/C          

    B)  4N/C

    C)  5 N/C           

    D)  None of these

    Correct Answer: D

    Solution :

     \[W=qV=q\overrightarrow{E}.\overrightarrow{d}\] \[4=0.2\times E\times (2\text{ }cos\text{ }60{}^\circ )\] \[4=0.2\times E\times 2\times 0.5\] \[E=\frac{4}{0.2}=20\,N/C\]


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