RAJASTHAN ­ PET Rajasthan PET Solved Paper-2003

  • question_answer
    If the maximum acceleration of motion of a particle is\[16\text{ }m/{{s}^{2}},\]and the maximum velocity is 24 m/s, then amplitude of the particle will be

    A)  36 m            

    B)  20 m

    C)  16 m            

    D)  None of these

    Correct Answer: A

    Solution :

     \[{{v}_{\max }}=a\omega =24m/s\] and   \[{{\alpha }_{\max }}=a{{\omega }^{2}}=16\,m/{{s}^{2}}\] \[\therefore \]Amplitude \[a=\frac{24\times 24}{16}=36\,m\]


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