RAJASTHAN ­ PET Rajasthan PET Solved Paper-2002

  • question_answer
    \[si{{n}^{6}}A+co{{s}^{6}}A+3si{{n}^{2}}Aco{{s}^{2}}A\]is equal to

    A)  3                

    B)  2

    C)  1                

    D)  0

    Correct Answer: C

    Solution :

     \[si{{n}^{6}}A+co{{s}^{6}}A+3\text{ }si{{n}^{2}}A\text{ }co{{s}^{2}}A\] \[={{({{\sin }^{2}}A)}^{3}}+{{({{\cos }^{2}}A)}^{3}}+3{{\sin }^{2}}A.{{\cos }^{2}}A\] \[=({{\sin }^{2}}A+{{\cos }^{2}}A)({{\sin }^{4}}A.+{{\cos }^{4}}A\] \[-{{\sin }^{2}}A{{\cos }^{2}}A)+3{{\sin }^{2}}A{{\cos }^{2}}A\] \[={{({{\sin }^{2}}A)}^{2}}+{{({{\cos }^{2}}A)}^{2}}+2{{\sin }^{2}}A{{\cos }^{2}}A\] \[={{({{\sin }^{2}}A+{{\cos }^{2}}A)}^{2}}=1\]


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