RAJASTHAN ­ PET Rajasthan PET Solved Paper-2002

  • question_answer
    Equation\[\frac{{{x}^{2}}}{2-r}+\frac{{{y}^{2}}}{r-5}+1=0\]represents an ellipse, if

    A)  \[r>5\]               

    B)  \[r>2\]

    C)  \[2<r<5\]         

    D)  None of these

    Correct Answer: C

    Solution :

     Standard equation of ellipse is \[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{b}^{2}}}=1\] where   \[{{a}^{2}}>1,{{b}^{2}}>1\] \[\therefore \] \[\frac{{{x}^{2}}}{2-r}+\frac{{{y}^{2}}}{r-5}+1=0\] \[\Rightarrow \] \[\frac{{{x}^{2}}}{2-r}+\frac{{{y}^{2}}}{r-5}=-1\] \[\Rightarrow \] \[\frac{{{x}^{2}}}{r-2}+\frac{{{y}^{2}}}{5-r}=1\] \[\therefore \] \[r-2>0\]and \[5-r>0\] \[\Rightarrow \] \[r>2\]and \[r<5\] \[\Rightarrow \]       \[2<r<5\]


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