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  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2002

  • question_answer
    Range of the function\[\frac{x+2}{|x+2|}\]is

    A)  \[\{-1,0,1\}\]

    B)  \[\{-1,1\}\]

    C)  \[[-1,1]\]

    D)  None of these

    Correct Answer: B

    Solution :

     \[\frac{x+2}{|x+2|}\] when\[x>-2,\]then function \[\frac{x+2}{x+2}=1\] when\[x<-2,\]then function\[\frac{x+2}{-(x+2)}=-1\] Hence, range is\[\{-1,1\}\].


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