A) \[\frac{4}{3}{{a}^{2}}sq\,units\]
B) \[\frac{8}{3}{{a}^{2}}sq\,units\]
C) \[\frac{2}{3}{{a}^{2}}sq\,units\]
D) \[\frac{5}{3}{{a}^{2}}sq\,units\]
Correct Answer: B
Solution :
Area between the vertex and latusrectum of the parabola\[{{y}^{2}}=4ax\] \[=2\int_{0}^{a}{\sqrt{4ax}}dx\] \[=2.2\sqrt{a}\left[ \frac{\frac{{{x}^{3/2}}}{3}}{2} \right]_{0}^{a}\] \[=4\sqrt{a}.\frac{2}{3}[{{a}^{3/2}}]=\frac{8}{3}{{a}^{2}}\]sq units
You need to login to perform this action.
You will be redirected in
3 sec
